INSERT INTO pricechange (id, productid, newprice, startdate) VALUES (1, 12345, ’34.99′, sysdate + 15); INSERT INTO pricechange (id, productid, newprice, startdate) VALUES (2, 23238, ’37.99′, sysdate + 20); …

and you have a list of a hundred product IDs that you’d like swap into those statements. It’d be neat if there was a simple way to do a find/replace on (\(\d+, )\d+, to replace with $1$productid, where each time it used the next product ID instead of $productid.

In the find box type <mytag>.+</mytag> In the replace box type whatever you want to replace it with .. for example <mynewtag>hello</mynewtag> check the “Regular Expression” checkbox

The . means any character, and the + means 1 or more of them – so .+ means any string with at least one character. If you want to match zero or more, use * instead of +

You can also use part of the matched search in the replacement. You do this by placing () around each part of the search you want to use, and referring to them in the replacement with $1, $2 etc. For example, suppose you have months and years in date tags january 1992 march 2003 etc., but instead you want: is the month is the year

You can do it like this: In the search field: ([A-Z,a-z]+) ([1-2][0-9][0-9][0-9]) In the replace field: \nis the month\nis the year\n

As mentioned, the brackets store the matches in variables: $1 and $2 based on the order of the bracket groups. [A-Z,a-z]+ means 1 or more upper or lower case characters [1-2][0-9][0-9][0-9] means 4 digits, the first must be 1 or 2 \n prints a new line

hope it helps

Any suggestions??